某程序的框图如图所示,则执行该程序,输出的结果a=
.
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考点分析:
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定义在R上的函数f(x)满足:f(1)=1,且对于任意的x∈R,都有f′(x)<
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,则不等式f(log
2x)>
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的解集为
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设函数f(x)(x∈R)满足f(-x)=f(x),f(x)=f(2-x),且当x∈[0,1]时,f(x)=x
3又函数 g(x)=|xcos(πx)|,则函数h(x)=g(x)-f(x)[
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]上的零点个数为
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设集合
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,集合B是f(x)=ln(1-|x|)的定义域,则A∪B
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设函数f(x)=
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,[x]表示不超过x的最大整数,则y=[f(x)]的值域是( )
A.{0,1}
B.{0,-1}
C.{-1,1}
D.{1,1}
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已知函数y=log
a(x+3)-1(a>0,且a≠1)的图象恒过定点A,若点A在直线mx+ny+1=0上,其中mn>0,则
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A.3
B.
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C.4
D.8
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