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如图,已知∠1 +∠2 =180°,∠DEF =∠A,求证:∠ACB = ∠D...

 如图,已知∠1 +∠2 =180°,∠DEF =∠A,求证:∠ACB = ∠DEB

6ec8aac122bd4f6e

 

见解析 【解析】证明:∵ ,     ∴······ 2分 ∴ EF∥AB·································· 3分 ∴ ∠DEF =∠BDE······························· 4分 ∵ ∠DEF=∠A ∴ ∠BDE =∠A································ 6分 ∴ DE∥AC·································· 7分 ∴ ∠ACB =∠DEB 8分 利用平角可求得EF∥AB,从而求得DE∥AC,最后得出结论
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