(2009•滨州)观察下列方程及其解的特征:
(1)x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/0.png)
=2的解为x
1=x
2=1;
(2)x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/1.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/2.png)
的解为x
1=2,x
2=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/3.png)
;
(3)x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/4.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/5.png)
的解为x
1=3,x
2=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/6.png)
;
…
解答下列问题:
(1)请猜想:方程x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/7.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/8.png)
的解为______;
(2)请猜想:关于x的方程x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/9.png)
=______的解为x
1=a,x
2=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/10.png)
(a≠0);
(3)下面以解方程x+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/11.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021230646687569455/SYS201310212306466875694016_ST/12.png)
为例,验证(1)中猜想结论的正确性.
【解析】
原方程可化为5x
2-26x=-5.
(下面请大家用配方法写出解此方程的详细过程)
考点分析:
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