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(2009•孝感)如图,将放置于平面直角坐标系中的三角板AOB绕O点顺时针旋转9...
(2009•孝感)如图,将放置于平面直角坐标系中的三角板AOB绕O点顺时针旋转90°得△A′OB′.已知∠AOB=30°,∠B=90°,AB=1,则B′点的坐标为( )
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A.(
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,
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)
B.(
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,
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)
C.(
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,
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)
D.(
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,
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)
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