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(2010•嘉兴)用代数式表示“a、b两数的平方和”,结果为 .
(2010•嘉兴)用代数式表示“a、b两数的平方和”,结果为 .
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(2010•嘉兴)如图,已知C是线段AB上的任意一点(端点除外),分别以AC、BC为斜边并且在AB的同一侧作等腰直角△ACD和△BCE,连接AE交CD于点M,连接BD交CE于点N,给出以下三个结论:①MN∥AB;②
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AB,其中正确结论的个数是( )
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=( )
A.
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B.
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C.
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D.
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