(2002•十堰)先阅读理解下列例题,再按要求完成作业.
例题:解一元二次不等式6x
2-x-2>0
【解析】
把6x
2-x-2分解因式,得6x
2-x-2=(3x-2)(2x+1).
又6x
2-x-2>0,所以(3x-2)(2x+1)>0
由有理数的乘法法则“两数相乘,同号得正”有(1)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/0.png)
或(2)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/1.png)
解不等式组(1)得x>
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/2.png)
,解不等式组(2)得x<-
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/3.png)
,所以(3x-2)(2x+1)>0的解集为x>
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/4.png)
或x<-
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/5.png)
作业题:①求分式不等式
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131021232523374984143/SYS201310212325233749841012_ST/6.png)
的解集.
②通过阅读例题和作业题①,你学会了什么知识和方法?
查看答案