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如图.在△ABC中,∠ACB=90°,CD⊥AB于D,AE平分∠BAC,分别于BC、CD交于E、F,EH⊥AB于H.连接FH,求证:四边形CFHE是菱形.
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先化简:(
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,然后从-1≤x≤2中选一个合适的整数作为x的值代入求值.
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如图,△ABC中,AD是中线,AE是角平分线,CF⊥AE于F,AB=5,AC=2,则DF的长为
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如图,反比例函数y=
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(x>0)的图象与矩形OABC的边长AB、BC分别交于点E、F且AE=BE,则△OEF的面积的值为
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