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一元二次方程2x2+4x-1=0的二次项系数 ,一次项系数 ,常数项为 .
一元二次方程2x2+4x-1=0的二次项系数 ,一次项系数 ,常数项为 .
考点分析:
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观察下列各式及证明过程:(1)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/0.png)
;(2)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/1.png)
;(3)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/2.png)
.
验证:
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/3.png)
;
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/4.png)
.
a.按照上述等式及验证过程的基本思想,猜想
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608024_ST/5.png)
的变形结果并进行验证;
b.针对上述各式反映的规律,写出用n(n≥1的自然数)表示的等式,并验证.
查看答案
(1)在实数范围内分解因式:
①9a
4-4b
4;
②x
2-2
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608023_ST/0.png)
x+3.
(2)比较
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608023_ST/1.png)
与
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608023_ST/2.png)
的大小.
查看答案
运用适当方法进行计算或化简:
(1)(
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608021_ST/0.png)
+1)
2006-2(
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608021_ST/1.png)
+1)
2007-2(
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608021_ST/2.png)
+1)
2006+2008;
(2)
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608021_ST/3.png)
.
查看答案
阅读题.
对于题目“化简并求值:
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/0.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/1.png)
,其中x=2”,小明与小东的解法不同.
小明的解法是:
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/2.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/3.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/4.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/5.png)
(1)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/6.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/7.png)
-x(2)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/8.png)
-x(3)
=-1(4)
小东的解法是:
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/9.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/10.png)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/11.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/12.png)
(1)
=
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/13.png)
+x-
![manfen5.com 满分网](http://img.manfen5.com/res/CZSX/web/STSource/20131103000053166760813/SYS201311030000531667608020_ST/14.png)
(2)
=x(3)
=2
请仔细阅读他们的解题过程:
(1)试说明谁的解答正确,谁的解答错误?并指出错在哪一步.
(2)试分析出现这种错误的原因是什么?
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