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tan和tan(-)是方程x2+px+q=0的两根,则p、q之间的关系是 ( )...

tan6ec8aac122bd4f6e和tan(6ec8aac122bd4f6e-6ec8aac122bd4f6e)是方程x2+px+q=0的两根,则p、q之间的关系是 (    )

 

A.p+q+1=0            B.p-q-1=0        C.p+q-1=0        D.p-q+1=0 

 

D 【解析】由根与系数关系得tan+tan(-)=-p,tan·tan(-)=q.  又=+(-) , ∴tan=tan[+( -)]=  ,故p-q+1=0. 故选D.
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