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(2008上海高考,5)若向量,满足||=1,| |=2,且与的夹角为,则|+|...

(2008上海高考,5)若向量6ec8aac122bd4f6e,6ec8aac122bd4f6e满足|6ec8aac122bd4f6e|=1,| 6ec8aac122bd4f6e|=2,且6ec8aac122bd4f6e6ec8aac122bd4f6e的夹角为6ec8aac122bd4f6e,则|6ec8aac122bd4f6e+6ec8aac122bd4f6e|=______________.

 

【解析】 试题分析:| +|2=(+)·(+)=·+·+2·=||2+||2+2||||cos=7|+|=. 考点:本题主要考查平面向量的数量积应用。
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