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将正三棱柱截去三个角(如图1所示A,B,C分别是△GHI三边的中点)得到几何体如...
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将正三棱柱截去三个角(如图1所示A,B,C分别是△GHI三边的中点)得到几何体如图2,则该几何体按图2所示方向的侧视图(或称左视图)为( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985015_ST/images1.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985015_ST/images2.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985015_ST/images3.png)
D.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985015_ST/images4.png)
考点分析:
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到直线x-y=0的距离等于
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的动点轨迹是曲线C,那么“点P在直线x-y-2=0上”是“点P在曲线C上”的 ( )
A.充分不必要条件
B.必要不充分条件
C.充要条件
D.既不充分也不必要条件
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已知
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985013_ST/0.png)
且
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,则
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与
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的夹角等于( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985013_ST/4.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985013_ST/5.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985013_ST/6.png)
D.
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已知函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985012_ST/0.png)
,x∈R,则f(x)是( )
A.最小正周期为π的奇函数
B.最小正周期为
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的奇函数
C.最小正周期为π的偶函数
D.最小正周期为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985012_ST/2.png)
的偶函数
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坐标平面上质点沿方向
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985011_ST/0.png)
前进,现希望在此平面上设置一直线l,使质点碰到直线l时,依据光学原理(入射角等于反射角)反射,并经反射后沿方向
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985011_ST/1.png)
前进,则直线l的其中一个方向向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024182835195598543/SYS201310241828351955985011_ST/2.png)
=
.
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对于每项均是正整数的数列A:a
1,a
2,…,a
n,定义变换T
1,T
1将数列A变换成数列T
1(A):n,a
1-1,a
2-1,…,a
n-1;对于每项均是非负整数的数列B:b
1,b
2,…,b
m,定义变换T
2,T
2将数列B各项从大到小排列,然后去掉所有为零的项,得到数列T
2(B);设A
是每项均为正整数的有穷数列,令A
k+1=T
2(T
1(A
k))(k=0,1,2,…).如果数列A
为4,2,1,则数列A
1为
.
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