已知函数f(x)=ax
3+bx
2+cx在x=±1处取得极值,且在x=0处的切线的斜率为-3.
(Ⅰ)求f(x)的解析式;
(Ⅱ)若过点A(2,m)可作曲线y=f(x)的三条切线,求实数m的取值范围.
考点分析:
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