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函数y=f(x)(x∈R),满足:对任意的x∈R,都有f(x)≥0且f2(x+1...
函数y=f(x)(x∈R),满足:对任意的x∈R,都有f(x)≥0且f
2(x+1)=7-f
2(x).当x∈(0,1)时,
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,则
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=
.
考点分析:
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直线
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与抛物线y
2=4x相交于A、B两点,与x轴相交于点F,若
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,则
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=
.
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程序框图如下,如果上述程序运行的结果为S=1320,那么判断框中横线上应填入的数字是
.
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若f(x)=
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,则f(1)+f(2)+f(3)…+f(2011)+f(
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)+f(
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)+…+f(
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)=( )
A.2009
B.2010
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C.2012
D.1
查看答案
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718008_ST/images0.png)
已知点P的双曲线
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718008_ST/0.png)
(a>0,b>0)右支上一点,F
1、F
2分别为双曲线的左、右焦点,I为△PF
1F
2的内心,若S
△IPF1=S
△IPF2+λS
△IF1F
2成立,则λ的值为( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718008_ST/1.png)
B.
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C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718008_ST/3.png)
D.
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下列说法:
①命题“存在x
∈R,使
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”的否定是
“对任意的
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”;
②若回归直线方程为
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,x∈{1,5,7,13,19},则
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718007_ST/3.png)
=58.5;
③设函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024184225469371861/SYS201310241842254693718007_ST/4.png)
,则对于任意实数a和b,a+b<0是f(a)+f(b))<0的充要条件;
④“若x∈R,则|x|<1⇒-1<x<1”类比推出“若z∈C,则|z|<1⇒-1<z<1”
其中正确的个数是( )
A.1
B.2
C.3
D.4
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