满分5 >
高中数学试题 >
函数y=ln(2x-1)(x>1)的反函数是( ) A.y=,(x>0) B.y...
函数y=ln(2x-1)(x>1)的反函数是( )
A.y=
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613914748/SYS201310251228006139147001_ST/0.png)
,(x>0)
B.y=e
2x+1(x>0)
C.y=
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613914748/SYS201310251228006139147001_ST/1.png)
,(x>0)
D.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613914748/SYS201310251228006139147001_ST/2.png)
(x>0)
考点分析:
相关试题推荐
已知集合P={x|x
2≤1},M={a}.若P∪M=P,则a的取值范围是( )
A.(-∞,-1]
B.[1,+∞)
C.[-1,1]
D.(-∞,-1]∪[1,+∞)
查看答案
(理)(1)证明不等式:ln(1+x)<
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123020_ST/0.png)
(x>0).
(2)已知函数f(x)=ln(1+x)-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123020_ST/1.png)
在(0,+∞)上单调递增,求实数a的取值范围.
(3)若关于x的不等式
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123020_ST/2.png)
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123020_ST/3.png)
≥1在[0,+∞)上恒成立,求实数b的最大值.
查看答案
设平面内两定点F
1(-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123019_ST/0.png)
,0),F
2(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123019_ST/1.png)
,0),直线PF
1和PF
2相交于点P,且它们的斜率之积为定值-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123019_ST/2.png)
.
(Ⅰ)求动点P的轨迹C
1的方程;
(Ⅱ)设M(0,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123019_ST/3.png)
),N为抛物线C
2:y=x
2上的一动点,过点N作抛物线C
2的切线交曲线C
1于P、Q两点,求△MPQ面积的最大值.
查看答案
各项为正数的数列{a
n}的前n项和为S
n,且满足:
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123018_ST/0.png)
.
(1)求a
n;
(2)设函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123018_ST/1.png)
,c
n=f(2
n+4)(n∈N
*),求数列{c
n}的前n项和T
n.
查看答案
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025122800613912332/SYS201310251228006139123017_ST/images0.png)
如图,在直三棱柱ABC-A
1B
1C
1中,AB=BC=2AA
1,∠ABC=90°,D是BC的中点.
(Ⅰ)求证:A
1B∥平面ADC
1;
(Ⅱ)求二面角C
1-AD-C的余弦值;
(Ⅲ)试问线段A
1B
1上是否存在点E,使AE与DC
1成60°角?若存在,确定E点位置,若不存在,说明理由.
查看答案