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设(x+1)4(x+4)8=a+a1(x+3)+a2(x+3)2+…+a12(x...
设(x+1)4(x+4)8=a+a1(x+3)+a2(x+3)2+…+a12(x+3)12,则a2+a4+…+a12=( )
A.256
B.96
C.128
D.112
考点分析:
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