设函数f(x)=ax+2(a<0),
(Ⅰ)不等式|f(x)|<6的解集为(-1,2),求a的值;
(Ⅱ)在(Ⅰ)的条件下,试求不等式
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的解集.
考点分析:
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①
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②
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•
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<0
③
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,B=30°④tanA+tanB+tanC>0.
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对于函数f(x)=x
2-2x,在使f(x)≥M成立的所有常数M中,我们把M的最大值-1叫做f(x)=x
2-2x的下确界,则函数
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的下确界为
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已知m>0,n>0,向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025123903233822429/SYS201310251239032338224013_ST/0.png)
,且
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,则
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的最小值是
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已知定义在R上的函数f(x)、g(x)满足
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,且f′(x)g(x)<f(x)g′(x),
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,若有穷数列
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(n∈N
*)的前n项和等于
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,则n等于 ( )
A.4
B.5
C.6
D.7
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