已知f(x)=sin
2wx+
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990011_ST/0.png)
sin2wx-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990011_ST/1.png)
(x∈R,w>0),若f(x)的最小正周期为2π.
(1)求f(x)的表达式和f(x)的单调递增区间;
(2)求f(x)在区间[-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990011_ST/2.png)
,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990011_ST/3.png)
]上的最大值和最小值.
考点分析:
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=cos(α+β).
(1)求证:tanβ=
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990010_ST/1.png)
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,求sinα的值、
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若锐角α、β满足(1+
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tanβ)=4,则α+β=
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若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124130699599097/SYS201310251241306995990006_ST/0.png)
=3,tan(α-β)=2,则tan(β-2α)=
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