已知a∈R,函数f(x)=2x
3-3(a+1)x
2+6ax
(Ⅰ)若a=1,求曲线y=f(x)在点(2,f(2))处的切线方程;
(Ⅱ)若|a|>1,求f(x)在闭区间[0,|2a|]上的最小值.
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