(1)由cos508°=-cos32°,cos144°=-cos36°,且cos32°>cos36°>0,可得-cos32°<-cos36°.
(2)由tan(-)=-tan,tan(- )=-tan,且tan<tan,可得-tan>-tan.
【解析】
(1)∵cos508°=cos148°=-cos32°,cos144°=-cos36°,
cos32°>cos36°>0,∴-cos32°<-cos36°,∴cos508°<cos144°.
(2)∵tan(-)=tan(-)=-tan,tan(- )=tan(-)=-tan,
tan<tan,∴-tan>-tan,故 tan(-)>tan(- ).