设函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525018_ST/0.png)
.
(1)求函数f(x)的单调区间、极值.
(2)若当x∈[a+1,a+2]时,恒有|f′(x)|≤a,试确定a的取值范围.
考点分析:
相关试题推荐
已知关于x的不等式(k
2+4k-5)x
2+4(1-k)x+3>0对任何实数x都成立,求实数k的取值范围.
查看答案
已知p:方程x
2+mx+1=0有两个不等的负实根,q:方程4x
2+4(m-2)x+1=0无实根.若p或q为真,p且q为假.求实数m的取值范围.
查看答案
请阅读下列材料:若两个正实数a
1,a
2满足a
12+a
22=1,那么a
1+a
2![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525015_ST/0.png)
.证明:构造函数f(x)=(x-a
1)
2+(x-a
2)
2=2x
2-2(a
1+a
2)x+1,因为对一切实数x,恒有f(x)≥0,所以△≤0,从而得4(a
1+a
2)
2-8≤0,所以a
1+a
2![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525015_ST/1.png)
.根据上述证明方法,若n个正实数满足a
12+a
22+…+a
n2=1时,你能得到的结论为
.
查看答案
实数x,y满足
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525014_ST/0.png)
,则
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525014_ST/1.png)
的取值范围为
.
查看答案
若对任意x>0,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223215259252502/SYS201311012232152592525013_ST/0.png)
≤a恒成立,则a的取值范围是
.
查看答案