定义在(-1,1)上的函数f(x)满足:①对任意x,y∈(-1,1),都有
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;②f(x)在(-1,1)上是单调递增函数,
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.
(1)求f(0)的值;
(2)证明:f(x)为奇函数;
(3)解不等式f(2x-1)<1.
考点分析:
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关于下列命题:
①函数y=tanx在第一象限是增函数;
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2(
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]上是增函数.
写出所有正确的命题的题号:
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函数
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,则f(-2)=
,f[f(-2)]=
.
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