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若集合A={x|2<x<3},B={x|(x-3a)(x-a)<0},且A⊆B,...
若集合A={x|2<x<3},B={x|(x-3a)(x-a)<0},且A⊆B,则实数a的取值范围是( )
A.1<a<2
B.1≤a≤2
C.1<a<3
D.1≤a≤3
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或-
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D.
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