满分5 >
高中数学试题 >
直线xcosa+ysina=4与圆x2+y2=4的位置关系是( ) A.相切 B...
直线xcosa+ysina=4与圆x2+y2=4的位置关系是( )
A.相切
B.相离
C.相交
D.不能确定
考点分析:
相关试题推荐
直线y=-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079971895/SYS201311031005290799718000_ST/0.png)
x+
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079971895/SYS201311031005290799718000_ST/1.png)
的斜率为( )
A.-
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079971895/SYS201311031005290799718000_ST/2.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079971895/SYS201311031005290799718000_ST/3.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079971895/SYS201311031005290799718000_ST/4.png)
D.
查看答案
已知向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/0.png)
=(x,y)与向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/1.png)
=(y,2y-x)的对应关系用
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/2.png)
=f(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/3.png)
)表示.
(1)证明对任意的向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/4.png)
、
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/5.png)
及常数m、n,恒有f(m
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/6.png)
+n
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/7.png)
)=mf(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/8.png)
)+nf(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/9.png)
)成立;
(2)设
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/10.png)
=(1,1),
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/11.png)
=(1,0),求向量f(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/12.png)
)与f(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/13.png)
)的坐标;
(3)求使f(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/14.png)
)=(p,q)(p、q为常数)的向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134028_ST/15.png)
的坐标.
查看答案
如图,已知O为△ABC的外心,a,b,c分别是角A、B、C的对边,且满足
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134027_ST/0.png)
.
(Ⅰ)证明:2a
2=b
2+c
2;
(Ⅱ)求
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134027_ST/1.png)
的值.
查看答案
已知
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134026_ST/0.png)
(I)当
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134026_ST/1.png)
时,解不等式f(x)≤0;
(II)若a>0,解关于x的不等式f(x)≤0.
查看答案
已知函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134025_ST/0.png)
求:
(Ⅰ)f(x)的最小正周期;
(Ⅱ)f(x)的单调递增区间;
(Ⅲ)f(x)在
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529079813495/SYS201311031005290798134025_ST/1.png)
上的最值.
查看答案