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已知函数f(n)=n2cos(nπ),且an=f(n)+f(n+1),则a1+a...
已知函数f(n)=n2cos(nπ),且an=f(n)+f(n+1),则a1+a2+a3+…+a100=( )
A.0
B.-100
C.100
D.10200
考点分析:
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