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函数y=ax-1+1(a>0且a≠1),无论a取何值,函数图象恒过一个定点,则定...
函数y=ax-1+1(a>0且a≠1),无论a取何值,函数图象恒过一个定点,则定点坐标为 .
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,则f(9)=
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若函数f(x)=log
ax在区间[a,2a]上的最大值是最小值的3倍,则a的值为( )
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如果函数f(x)=x
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已知f(x)的定义域为[-2,4],则f(3x-2)的定义域为( )
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C.y=x
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