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要得到函数y=sin(2x+1)的图象,只要将函数y=sin2x的图象( ) A...
要得到函数y=sin(2x+1)的图象,只要将函数y=sin2x的图象( )
A.向左平移1个单位
B.向右平移1个单位
C.向左平移
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248004_ST/0.png)
个单位
D.向右平移
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248004_ST/1.png)
个单位
考点分析:
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函数y=x
2-1(x≥0)的反函数是( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248003_ST/0.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248003_ST/1.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248003_ST/2.png)
D.
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向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248002_ST/0.png)
=(1,-2),
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248002_ST/1.png)
=(6,3),则
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248002_ST/2.png)
与
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248002_ST/3.png)
的夹角为( )
A.60°
B.90°
C.120°
D.150°
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若a、b是任意实数,且a>b,则下列不等式成立的是( )
A.a
2>b
2B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953624832/SYS201311031024079536248001_ST/0.png)
C.lg(a-b)>0
D.
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已知全集U={0,1,2,3,4,5,6,7,8,9},集合A={0,1,3,5,8},集合B={2,4,5,6,8},则(C
UA)∩(C
UB)=( )
A.{5,8}
B.{7,9}
C.{0,1,3}
D.{2,4,6}
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已知抛物线D的顶点是椭圆
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102407953481797/SYS201311031024079534817021_ST/0.png)
的中心,焦点与该椭圆的右焦点重合.
(Ⅰ)求抛物线D的方程;
(Ⅱ)已知动直线l过点P(4,0),交抛物线D于A、B两点.(i)若直线l的斜率为1,求AB的长;(ii)是否存在垂直于x轴的直线m被以AP为直径的圆M所截得的弦长恒为定值?如果存在,求出m的方程;如果不存在,说明理由.
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