已知函数 f(x)=ax+1nx(a∈R).
(1)若a=2,求曲线y=f(x)在x=l处切线的斜率.
(2)设 g(x)=x
2-2x+2,若对任意x
1∈(0,+∞),均存在x
2∈[0,1],使得f(x
1)<g(x
2),求a的取值范围.
考点分析:
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