可设这十个数依次为a1,a2,a3,a4,a5,a6,a7,a8,a9,a10(其中a1=1,a10,=3)则可得插入的这8个数之积为a2a3a4a5a6a7a8a9然后再根据在等比数列{an}中若m+n=p+q则aman=apaq即可求出a2a9=a3a8=a4a7=a5a6=a1a3=3进而可求出这8个数之积a2a3a4a5a6a7a8a9=3×3×3×3=81
【解析】
设这十个数依次为a1,a2,a3,a4,a5,a6,a7,a8,a9,a10(其中a1=1,a10,=3)
∴插入的这8个数之积为a2a3a4a5a6a7a8a9
∵a2a9=a3a8=a4a7=a5a6=a1a3=3
∴a2a3a4a5a6a7a8a9=3×3×3×3=81
故选D