等差数列{an}中,a7=4,a19=2a9.
(1)求{an}的通项公式;
(2)设bn=
,求数列{bn}的前n项和Sn.
设数列{an}满足a1=2,a2+a4=8,且对任意n∈N*,函数f(x)=(an-an+1+an+2)x+an+1cos x-an+2sin x满足f′
=0.
(1)求数列{an}的通项公式;
(2)若bn=2(an+
),求数列{bn}的前n项和Sn.
设等差数列{an}的前n项和为Sn,且S4=4S2,a2n=2an+1.
(1)求数列{an}的通项公式;
(2)设数列{bn}满足
+
+…+
=1-
,n∈N* ,求{bn}的前n项和Tn.
正项数列{an}满足
-(2n-1)an-2n=0.
(1)求数列{an}的通项公式an;
(2)令bn=
,求数列{bn}的前n项和Tn.
已知等差数列{an}的前n项和Sn满足S3=0,S5=-5.
(1)求{an}的通项公式;
(2)求数列
的前n项和.
数列{an}满足an+1+(-1)nan=2n-1,则{an}的前60项和为( )
(A)3690 (B)3660 (C)1845 (D)1830
