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如图,已知直角梯形ABCD中,AD∥BC,∠BCD=90°,BC=CD=2AD,...
如图,已知直角梯形ABCD中,AD∥BC,∠BCD=90°,BC=CD=2AD,E、F分别是BC、CD边的中点,连接BF、DE交于点P,连接CP并延长交AB于点Q,连接AF,则下列结论:①CP平分∠BCD;②四边形ABED为平行四边形;③CQ将直角梯形ABCD分为面积相等的两部分;④△ABF为等腰三角形,其中不正确的有( )
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A.1个
B.2个
C.3个
D.0个
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