分解因式:2x2-4x+2= .
考点分析:
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如图,正方形ABCD中,点E在边BC上,且CE=2BE.连接BD、DE、AE,且AE交BD于F,OG为△BDE的中位线.下列结论:①OG⊥CD;②AB=5OG;③
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如图,矩形纸片ABCD沿过点B的直线折叠,点A落在BC边上的点E处,还原后,再沿过点E的直线折叠,点A落在BC边上的点F处,则tan∠FAB=( )
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D.
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如图,在Rt△ABC中,∠ACB=90°,BC=3,AC=4,AB的垂直平分线DE交BC的延长线于点E,则CE的长为( )
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