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若曲线y=x4的一条切线l与直线x+4y-8=0垂直,则l的方程为( ) A.4...
若曲线y=x4的一条切线l与直线x+4y-8=0垂直,则l的方程为( )
A.4x-y-3=0
B.x+4y-5=0
C.4x-y+3=0
D.x+4y+3=0
考点分析:
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