(1)由题意可得,g[g(x)]=g(4x)=,f[g(x)]=f(4x)=,g(f(x))=g(2x)=,由g[g(x)]>g[f(x)]>f[g(x)],代入可求
(2)y=4x-3•2x+3=22x-3•2x+3,依题意有,解不等式可求
【解析】
(1)g[g(x)]=g(4x)=,f[g(x)]=f(4x)=,g(f(x))=g(2x)=
∵g[g(x)]>g[f(x)]>f[g(x)]
∴
∴22x+1>2x+1>22x,
∴2x+1>x+1>2x,
解得0<x<1
(2)y=4x-3•2x+3=22x-3•2x+3,依题意有
即,
∴2≤2x≤4或0<2x≤1,
由函数y=2x的单调性可得x∈(-∞,0]∪[1,2].